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Depending an whether you mean:
11 - x2
or:
11 - x + 2
For the sake of thoroughness, we'll look at both:
∫(11 - x2) dx = 11x - x3/3 + C
∫(11 - x + 2) dx = ∫(13 - x) dx = 13x - x2/2 + C
11x = 8x-6.............. 11x-8x = -6................... 3x= -6 x = -2
11x(2x - 1) = 0 so either 11x = 0 or x = ½
12x - 5 = 11x + 5(1) add 5 to both sides:12x - 5 + 5 = 11x + 5 + 512x = 11x + 10(2) next subtract 11x from both sides:12x - 11x = 11x - 11x + 10x = 10
Write as an equation with division before subtraction. 5/11x-7=2 5/11x=9 mult both sides by 11x 5=99x 99x=5 x=5/99
6 + 11x - 60 =6 - 60 + 11x = -54 + 11x = 11x -54