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5x-2y=20
Subtract 5x on both sides to see what y equals.
-2y=20-5x
Divide by -2 on each side.
y=-10+(5/2)x or
y = (5/2)x - 10 (the slope-intercept form of the equation of a line, where the y-intercept is -10)
Add 2y to both sides to see what x equals.
5x=20+2y
Divide by 5 on each side.
x=4+2/5y or
x = (2/5)y + 4, where 4 is the x-intercept.
(all this work is to show that when the value of y is zero, the line cuts the x-axis at 4)
Now plug in what x equals into the equation of what y equals to get the exact value of y.
y=-10+5/2x
y=-10+5/2(4+2/5y)
Distribute the 5/2 to the (4+2/5y) in parentheses.
y=-10+10+y
Combine like terms.
y=y+0
Subtract y on both sides.
0y=0
Divide by 0 on each side.
y=0
Now plug in what y equals to into what x equals to find the exact value of x.
x=4+2/5y
x=4+2/5(0)
x=4+0
x=4
Your first solution to the data is (4,0).
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What is the ordered pair to 2x-5y equals -1?
The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.
What are the x and and y intercepts for the graph of 2x - 5y equals 10?
x intercept = (5, 0) y intercept = (0, -2)
What is the equation of the line 3 -4 and perpendicular to the line of 5x -2y equals 3?
Answer: y = -2/5x-14/5 which also can be written as 5y = -2x-14 or in the general form of the equation of a straight line as 2x+5y+14 = 0
-8x plus 5y equals 10?
x=0 y=2
How would you put 5y equals 25 in standard form?
5y=25x 25x=5y -5y 25x-5y=0
Is 0 -2 a solution of 2x - 5y equals 10?
Yes it is!
What is the slope-intercept form of the equation -2x 5y-15?
0 = -2x + 5y - 15 -5y = -2x - 15 y = 2x/5 + 3
2x - 5y plus 15 equals 0 written in slope-intercept form?
2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
What is the x intercept for the equation -2x plus 5y equals -10?
(5, 0)
How do you make 2x-5y equals 5 into points?
2x-5y=5 In order to solve this linearly(in points), you must plug in numbers into x or y, then solve the equation for the other variable. For example: if you plug 0 into x, or into y. You will need to do this with at least two points, three two be safe. 2(0)-5y=5 2x-5(0)=5 0-5y=5 2x=5 0-5y-0=5-0 2x/2=5/2 -5y=5 x=5/2 -5y/-5=5/-5 (5/2,0) y=-1 You then create a graph and plot the points. Next, draw a (0,-1) connecting the two points, and...voila! you have put 2x-5y=5 into points on a line.
2x plus 5y equals 0 x - 5y equals -15?
(-5, 2)
Which point lies on 2x plus 5y equals 10?
First, in this form. Y =mX + c2X + 5Y = 105Y = - 2X + 10Y = (-2/5)X + 2Y = 2----------0 out equation(- 2/5)X + 2 = 0(- 2/5)X = - 2X = 5---------(0, 2) and (5, 0)------------------------------ points on the line
What are the x and y intercepts of -2x equals 20 plus 5y?
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
What is the ordered pair to 2x-5y equals -1?
The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.
How would 2x plus 5y plus 30 equals 0 be worked out?
2X+5Y+30=0 So you subtract 30 from each side. 2X+5Y+30-30=0-30. So you know 2X+5Y=-30. now there are many different possibilities for X and Y unless there is a specification. here are some possibilities=X=0,Y=6 or X=A5,Y=0 or X=5,Y=4
What is the solution of 5 y plus x equals 0?
5y + x = 0 subtract 5y from each side, then x = -5y
What is the answer to 5x plus 10 plus 5y minus 3x plus 1?
5x+10-5y-3x+1=0 <--You start with this. Then move the 10 and 1 to the other side by subtracting them. 5x-5y-3x=-11<--Next combine the x's 2x-3y=-11<--This is the simplified answer.
