x intercept = (5, 0)
y intercept = (0, -2)
-2x=2y+5 +2x -2y -2y=2x+5 /-2 y=-1/1+2.5
2x-3 = 17 2x = 17+3 2x = 20 x = 10
2x + 5 = 25 2x = 20x = 10
(6,0) and (0,2)
2x+5y=20 Solve for y -2x -2x 5y=20-2x 5 5 5 y=4-2x 5
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
The result will be a plane that intercepts the x-, y-, and z-axes at +9, +6, and +3, respectively.
x: x = 15 y: y = 10 z: z = -5
12
10
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
-2
-2
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
-2x plus 3y equals 1