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Yes. 1,239 / 21 = 59
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Is 21 divisible by 2 3 or 5?
21 is not divisible by 2 nor 5, but it is divisible by 3. To be divisible by 2 the last digit must be even (one of {0, 2, 4, 6, 8}; the last digit 1 is not one of these, thus 21 is not divisible by 2 To be divisible by 3 sum the digits and if this total is divisible by 3, then so is the original number; the test can be repeated on the sum, so by repeatedly summing the digits of the totals until a single digit remains only if that single digit is 3, 6 or 9 is the original number divisible by 3. 21 → 2 + 1 = 3 which is divisible by 3 so 21 is divisible by 3. To be divisible by 5, the last digit must be 0 or 5. The last digit of 21 is 1 which is not 0 nor 5, thus 21 is not divisible by 5.
What number is between 21 and 39 that is divisible by 2 and 5?
If its divisible by 5 AND 2 it must be divisible by 10 So you just have to pick the only number between 21 and 39 that's divisible by 10
What number is divisible by 3 and 7?
21
Which number between 190 and 200 is divisible by 9?
Divisibility pattern for 7?
you have to separate them and if both of them are in the 7 times table it is. eg.3521 is it divisible by 7 35 + 21 the 35 is in the 7 timetable and so is the 21 so there both divisible by 7. another eg.1442 14 + 21 14 is divisible by 7 and so is 21 yes it is . thank u
Is 6 divisible by 1239?
No. 6 is less than 1239 so it cannot be divisible by it. Nor is 1239 divisible by 6: all multiples of 6 are even but 1239 is odd, so it cannot be divisible by 6.
Is 9 divisible by 1239?
No. 9 is less than 1239 so it cannot be divisible by it. Nor is 1239 divisible by 9. To test if a number is divisible by 9 add the digits and if this sum is divisible by 9 then so is the original number. As the test can be applied to the sum, repeating the summing until a single digits remains means the original number is divisible by 9 only if this single digit (also called the digital root of the number) is 9. (if it is not 9, it gives the remainder when the original number is divided by 9). For 1239: 1 + 2 + 3 + 9 = 15 → 1 + 5 = 6 which is not 9, so 1239 is not divisible by 9 (it has a remainder of 6 when divided by 9).
What is the divisible of 21?
The numeral '21' is evenly divisible by 21, 7, 3, and 1.
What is divisible by 105 and 21?
They're both divisible by 1,3,7, and 21.
What is divisible in 21 and 37?
There is nothing that is divisible in 37 and 21. Because 37 is a prime number. However, 21 is divisible by 3 and 7.
Why is 21 divisible by 1 21 3 and 7?
Because 21 is a multiple of 1, 3, 7 and 21.
Why is the number 21 composite?
Because 21 is divisible by numbers other than 1 and 21. 21 is divisible by 1, 3, 7, 21
How is a no divisible by 21?
By any multiples of 21
Example of divisibility rule for 21?
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
What is 1239 x 6789?
1239 x 6789 = 8,411,571
What is 400 times 1239?
400 x 1239 = 495600
Is 66 divisible by 21?
No, it is not.
