Yes.
250 is divisible by 1, 2, 5, 10, 25, 50, and 250.
No, as 250 divided by 2 = 125.5
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.
250 is divisible by 1, 2, 5, 10, 25, 50, and 250.
There are 193 numbers in between 1 and 250 that are divisible by 2, 3, 5, or 7. Note that if you are not including 250 (so if you meant 1 - 249), then there are 192.
No, as 250 divided by 2 = 125.5
No. For any number to be a factor of another number, the second number must be divisible by (ie a multiple of) the first number. To check for divisibility by 3 add the digits of the number together and if this sum is divisible by 3, then so is the original number. 250 → 2 + 5 + 0 = 7; 7 is not divisible by 3, so 250 is not divisible by 3 → 3 is not a factor of 250. The factors of 250 are: 1, 2, 5, 10, 25, 50, 125, 250.
250 i believe!
No, 250/3 = 83 remainder 1 3 is not a factor of 250 : the prime factors are 2 x 5 x 5 x 5 (2 x 53).
3 digit numbers less than 300 that are divisible by 2 and 5 are be numbers ranging from 100 to 290. 120, 150, 180, 210, 240, and 270 are divisible by 3, so those are crossed off the list. The sum of the digits is 7. 160 and 250 are possible answers. 1+6+0 = 7 and 2+5+0 = 7. 160/2 = 80 and 160/5 = 32. 250/2 = 125 and 250/5 = 50. I can either be 160 or 250.
160, 250
To determine how many of the first 250 triangular numbers are divisible by 5, we first note that the (n)-th triangular number is given by the formula (T_n = \frac{n(n+1)}{2}). A triangular number is divisible by 5 if either (n) or (n+1) is divisible by 10 (since one of them will be even, ensuring that the division by 2 does not affect divisibility). Among the first 250 integers, there are 50 multiples of 5 (for (n)) and 25 multiples of 10 (for (n+1)). Thus, there are (50 + 25 = 75) triangular numbers that are divisible by 5.
-- Neither 2 nor 5 is divisible by 18. -- 18 is divisible by 2, but not by 5.
1, 2, 4, 5, 10, 20, 25, 50, 100, 125, 250, 500
No, it is not a prime number, it is divisible by 2, 625, 5, 250, 10, 125, and probabaly more than that. Primes are only divisible by 1 and itself.