To find the product of 2xy and x, you multiply the coefficients (2 and 1) to get 2, then multiply the variables x and x to get x^2, and finally multiply the variables y and 1 to get y. Therefore, the result of 2xy times x is 2x^2y.
8-x2y 8-2xy 2xy-8
2xy substitute 3 for y and 5 for x 2(5)(3) = 30
xy + xy = 2xy
You can expand (x + y)2 into x2 + 2xy + y2
Since 2xy is a factor of 2x2y, it is automatically the GCF.
2xy
The possibilities are infinite. One set: 1. 2xy 2. 2x2y 3. 2x4y
To find the product of 2xy and x, you multiply the coefficients (2 and 1) to get 2, then multiply the variables x and x to get x^2, and finally multiply the variables y and 1 to get y. Therefore, the result of 2xy times x is 2x^2y.
Not sure. There is no particular name for x2 and 2xy (both include x) in x2 + 2xy + y2 + y3
2x2y
2x2y
2xy + 6xy = 8xy
(x + 4y)(x - 6y)
2x2y
2x2y
2xy - 4x + 8y - 16 can be factored.(2xy - 4x) + (8y - 16)2x(y - 2) + 8(y - 2)Since y-2 is the same as the other, it would turn out like this:(2x + 8)(y - 2):]