Q: Is 305 divisible by 305

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1, 3, 5, 15, 61, 183, 305, 915.

Only 315. To be divisible by 3 numbers have to add to a number divisible by 3 (3+1+5 =9). To be disable by 5, number has to end in a 5 or 0

5, yes. 2, 3, 6, 9, 10, no.

305

305

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No.

No.

To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.

305 is divisible by any of its factors, which are 1, 5, 61, and 305.

No. 305 is divisible by 1, 5, 61, 305.

False. 305 can only be divided by five and also 1, 61 and 305.

All multiples of 305 (which are infinite) including 305, 610, 915, 1220, 1525, 1830 . . .

5All Factors of 305:1, 5, 61, 305

305 can only be [exactly] divided by 5 and not 2, 3, 6, 9 nor 10.Divisibility tests:2: NoNumber must be even (last digit divisible by 2). Last digit is 5 which is not even, so the whole number (305) not divisible by 2.3: NoAdd up the digits of the number; if this sum is divisible by 3, then the original number is divisible by 3: 3 + 0 + 5 = 8 which is not divisible by 3, so the original number (305) is not divisible by 3.5: YesLast digit is 0 or 5. Last digit is 5, so 305 is divisible by 5. 6: No6 = 2 x 3, so number must pass both tests for divisibility of 2 and 3; 305 fails tests for (both) 2 and 3 (above), so is not divisible by 6. 9: NoAdd up the digits of the number; if this sum is divisible by 9, then the original number is divisible by 9: 3 + 0 + 5 = 8 which is not divisible by 9, so the original number (305) is not divisible by 9.10: NoThe last digit of the number must be 0. Last digit is 5, so 305 is not divisible by 10.

No; for a number to be divisible by 10, the last number (ones place) must be zero.

no because its not an even number.

Yes to 5. No to 3.