No.
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Yes to 5. No to 3.
To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.
All multiples of 305 (which are infinite) including 305, 610, 915, 1220, 1525, 1830 . . .
No; for a number to be divisible by 10, the last number (ones place) must be zero.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.