yes!!!!
However, the answer has a remainder of '1'
49/3 = 16 remainder '1'.
NB It does NOT gove a whole number answer!!!!!
Yes. The answer is 49.
Besides 49 & 98? The numbers divisible by 49 are infinite.
The divisibility rule for 3 is as follows: If the sum of the digits of a number is divisible by 3 then the number is divisible by 3. For example, the number 21 is divisible by 3 since 2+1=3, and 3 is divisible by 3. The number 49 is not divisible by 3 since 4+9=13, and 13 is not divisible by 3.
1, 3, 7, 9, 21, 49, 63, 147, 441
Yes: 49 ÷ 7 = 7
No, 3 cannot go into 49 evenly because 49 is not divisible by 3 without leaving a remainder.
1, 3, 49, and 147
1, 3, 49, and 147
No. 49 is only divisible by 1, 7 and 49.
Yes. The answer is 49.
Besides 49 & 98? The numbers divisible by 49 are infinite.
The divisibility rule for 3 is as follows: If the sum of the digits of a number is divisible by 3 then the number is divisible by 3. For example, the number 21 is divisible by 3 since 2+1=3, and 3 is divisible by 3. The number 49 is not divisible by 3 since 4+9=13, and 13 is not divisible by 3.
No, but 98 is evenly divisible by 1, 2, 7, 14, 49, 98.
All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
The factors of 18 are: 1, 2, 3, 6, 9, 18 The factors of 49 are: 1, 7, 49
49 is divisible by 1, 7 and 49
The reason is that 49 is divisible with numbers other than 1 and itself. 49 is divisible by 1, 7 and 49.