Common Prime number is 2 only.
The LCM is 56.
They are: 7 and 8
The factors of 56 are: 1 2 4 7 8 14 28 56 The prime factors are: 2 x 2 x 2 x 7 http://www.classbrain.com/artteach/publish/article_48.shtml?num=56&worksp=
To find the four numbers that multiply together to make 56, we can use prime factorization. First, we factorize 56 into its prime factors: 56 = 2 x 2 x 2 x 7. Then, we group these factors in pairs to find four numbers: 2 x 2 = 4, 2 x 7 = 14. Therefore, the four numbers that multiply together to make 56 are 2, 2, 2, and 7.
1 * 56 = 56 2 * 28 = 56 4 * 14 = 56 7 * 8 = 56 8 * 7 = 56 14 * 4 = 56 28 * 2 = 56 56 * 1 = 56
56 and 105
1, 2, 4, 7, 8, 14, 28, 56 2 and 7 are prime.
The second one.
The prime numbers (factors) of 56 are: 2 and 7
The prime numbers (factors) of 56 are: 2 and 7
To find the prime numbers of 56, start with two numbers that when multiplied together equal 56. For example: 2 x 28 = 56. Two is prime, but 28 is composite, so it needs to be factored. 2 x 2 x 14 = 56. Now, 14 is prime, so factor it. 2 x 2 x 2 x 7 = 56. All the factors are now prime, so the prime factors are 2 x 2 x 2 x 7.
Numbers cannot "make" another number prime. If you are looking for the prime factorization of 56, it is 23 * 7.
56=2x2x2x7
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
It is 70 or 42 that have exactly 3 prime factors
Well, darling, you're out of luck on this one. Prime numbers are only divisible by 1 and themselves, so there's no way to add three of them together to get 56. You might want to brush up on your math facts before trying to stump me next time.
The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.