yes
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The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
There are only three proper factors of 81; they are 3, 9 and 27.81 is also divisible by 1 and by itself, but mathematicians regard these as improper factors because they are trivial. Every natural number is divisible by itself and by unity.
Every number is divisible by any non-zero number. Furthermore, it is evenly divisible by 3.
150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.
Yes every natural no. a factor and multiple of 1