1, 2, 3 ,4 ,5, 6 ,7, 8 ,9 ,11, 22, 33, 44, 55, 66 ,77 ,88, 99, 101 ,111, 121 ,131 ,141 ,151 ,161, 171 ,181 ,191, 202, and so forth
1001,1111,1221,1331,1441,1551,1661,1771,1881,1991,2002,2112,2222,2332,2442,2552,2662,2772,2882,2992,3003,3113,3223,3333,3443,3553,3663,3773,3883,3993,4004,4114,4224,4334,4444,4554,4664,4774,4884,4994: 40 numbers in all.
There are 9 palindromic numbers between 400 and 500. A palindromic number reads the same forwards and backwards. The palindromic numbers in this range are 404, 414, 424, 434, 444, 454, 464, 474, and 484.
Twenty.
6,1,8
There are 9 palindromic numbers between 0 and 100: 11, 22, 33, 44, 55, 66, 77, 88 and 99.
That's an infinite list.
There are not just 13 non-palindromic numbers. Most numbers are non-palindromic.
There are 90 palindromic numbers between 100 and 1000
No.
Nobody went out to create them: some numbers simply happen to be palindromic and others don't.
infinite
777717711771817718817...
No.
there are 10 palindromic numbers between 9000 and 10000 9009,9119,9229,9339,9449,9559,9669,9779,9889,9999!!!
As 20569.8 is not palindromic, any number that is like it must contain that property and similarly be non-palindromic, so no.
I guess that the smallest would be zero, if you don't consider negative numbers. There is no largest palindromic number - you can make them as large as you like.
There are more 12-digit palindromic numbers than 11-digit palindromic numbers. This is because the number of possible 12-digit palindromic numbers is greater than the number of possible 11-digit palindromic numbers. In general, the number of palindromic numbers of length n is 9 * 10^((n-1)/2), so for 11-digit palindromic numbers, there are 9 * 10^5 = 900,000 possibilities, while for 12-digit palindromic numbers, there are 9 * 10^6 = 9,000,000 possibilities.