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You basically have to take the antilogarithm - in this case, in base 3 - on both sides of the equation. That will make the "log3..." disappear on the left side. Antilog (base 3) means you raise 3 to the specified power.
log3(x)=4 x=3^4 x=81
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3
log37 - log3x = 4 log3(7/x) = 4 7/x = 34 = 81 x = 7/81
3x = 12 log3(12) = 2.261859507 x = 2.261859507
Find 102a if log2=a and log3=b B has no purpose in this question If a=log2, then 102a =102(log2)