5 * 5 + 5
6 * 6 -6
3^3 +3
999
Using the word "combinations" in the English sense (as opposed to mathematical sense the expert has used) where it often used in the mathematical sense of the word "permutations": Assuming the hundreds digit must be at least 1 (eg 99 = 099 is not considered a three digit number), then: 9 x 10 x 10 = 900.
Your 10th birthday is your first two-digit birthday. In the same way, your 100th birthday is your first three-digit birthday.
A palindrome reads the same forward and in reverse. This tells me that at leastthe first digit and the last digit must be the same. So it's not possible to have a6-digit palindrome "with no same digits".The largest 6-digit palindrome, with just enough repetition of digits to make it apalindrome and no more, would be 987,789 .
0.3 is the same as 3/10 (three tenths)so the digit in the tenths place would be 3
There are 10 digits, but for a three digit number the first number cannot be a 0. Thus: there is a choice of 9 digits for the first (and last digit which must be the same), with 10 choices of digit for the second (middle) digit, making 9 × 10 = 90 such palindromic numbers.
300
No.
It is not possible since a palindrome, by definition, requires the last digit to be the same as the first.
Multiplying a 2-digit number by a 1-digit number involves multiplying the digits in the ones and tens place and then adding the products. Similarly, multiplying a 3-digit number by a 1-digit number follows the same principle, where you multiply the digits in the ones, tens, and hundreds place and then add the products. The main difference is that in the latter case, you are dealing with three sets of digits to multiply and add, whereas in the former, you only have two sets of digits.
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
The greatest 3 digit number is 999, and all three digits are the same.
10+10+10, 0+1+2
999
9998888
Your 10th birthday is your first two-digit birthday. In the same way, your 100th birthday is your first three-digit birthday.
Using the word "combinations" in the English sense (as opposed to mathematical sense the expert has used) where it often used in the mathematical sense of the word "permutations": Assuming the hundreds digit must be at least 1 (eg 99 = 099 is not considered a three digit number), then: 9 x 10 x 10 = 900.