It won't work for all numbers. I tried with 1 and got a 0.230769...
Yes, when multiplying or dividing two negatives the result is a positive number.
In all of these cases the result is positive.
the number that results is a PRODUCT. multiplying any two figures will always result in a product of those two figures as such multiplying a PARTICULAR NUMBER by ANY NUMBER does not change anything, they still result in a PRODUCT of those two numbers.
Multiplying a sum by a number gives the same result as multiplying each addend by the number and then adding the products together.
The question first needs to be rewritten as an equation. This can be done as follows: nx = n/0.125 where n is any number. The first step is to divide both sides by n, to give us x=1/0.125 This can then be calculated at x=8 Thus the value of x when multiplying a number by x yields the same result as dividing that number by 0.125 is 8.
because of mathematical equivalence: it doesn't change the result
Multiplying or dividing a positive and negative gives a negative result. Multiplying or dividing two negatives gives a positive result.
By multiplying the percentage number then dividing the end result by 100.
The result is a vector.
0.66 is exactly double 0.33. Since dividing by a number is the same as multiplying by its reciprocal, dividing by double a number is the same as multiplying by half the number. As a result, the answer is half as large.
Yes, when multiplying or dividing two negatives the result is a positive number.
Multiplying a positive and negative number will give a negative result. The result is a negative number.
It's a positive number. Here's the rule: In multiplication and division . . . -- If both numbers have the same sign, then the result of multiplying or dividing them is positive. -- If the two numbers have different signs, then the result of multiplying or dividing them is negative.
The result is their product.
A square number
In all of these cases the result is positive.
The result of multiplying numbers is called the product.