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We have:

x^2 + y^2 + 10x + 2y + 22 = 0

We want to find the standard equation for a circle, which is:

(x - a)^2 + (y - b)^2 = r^2

Where (a,b) is the center of the circle, and the radius is r.

Regroup with like variables, and move the constant term to the right:

x^2 + 10x + y^2 + 2y = -22

complete the square on both quadratics on the left:

x^2 + 10x + c + y^2 + 2y + d = -22 + c + d

find c, such that 2 * (c^(1/2)) = 10 and find d, such that 2 * (d^(1/2)) = 2

c = 25 d = 1

x^2 + 10x + 25 + y^2 + 2y + 1 = -22 + 25 + 1

(x + 5)^2 + (y + 1)^2 = 4

We now have the standard equation for a circle, which gives us a center at:

(-5, -1)

and which has a radius of 2.

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