We have:
x^2 + y^2 + 10x + 2y + 22 = 0
We want to find the standard equation for a circle, which is:
(x - a)^2 + (y - b)^2 = r^2
Where (a,b) is the center of the circle, and the radius is r.
Regroup with like variables, and move the constant term to the right:
x^2 + 10x + y^2 + 2y = -22
complete the square on both quadratics on the left:
x^2 + 10x + c + y^2 + 2y + d = -22 + c + d
find c, such that 2 * (c^(1/2)) = 10 and find d, such that 2 * (d^(1/2)) = 2
c = 25 d = 1
x^2 + 10x + 25 + y^2 + 2y + 1 = -22 + 25 + 1
(x + 5)^2 + (y + 1)^2 = 4
We now have the standard equation for a circle, which gives us a center at:
(-5, -1)
and which has a radius of 2.
9
Equation of the circle: (x-3)^2 +( y+13)^2 = 169
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
The equation of a circle can be written in the form (x-h)2 + (y - k)2 = r2, where r is the radius, and (h,k) is the center. So for your example, the equation would be: (x- 5)2 + (y - 3)2 = 72
There are probably several ways to approach it; one general equation for the circle is: (x - a)2 + (y - b)2 = r2 This describes a circle with center at coordinates (a, b), and with a radius of r.
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
9
depends on the equation.
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
The equation of the circle is: x^2 + y^2 = 81
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
The equation of the circle is: (x+3.2)^2 +(y+2.1)^2 = 18.49
Equation of circle: (x-2)^2 +(y+9)^2 = 49
Center of circle: (6, 8) Radius of circle: 3
A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1
a diameter