q + p
If p then q is represented as p -> q Negation of "if p then q" is represented as ~(p -> q)
By definition, every rational number x can be expressed as a ratio p/q where p and q are integers and q is not zero. Consider -p/q. Then by the properties of integers, -p is an integer and is the additive inverse of p. Therefore p + (-p) = 0Then p/q + (-p/q) = [p + (-p)] /q = 0/q.Also, -p/q is a ratio of two integers, with q non-zero and so -p/q is also a rational number. That is, -p/q is the additive inverse of x, expressed as a ratio.
The truth values.
p --> q and q --> p are not equivalent p --> q and q --> (not)p are equivalent The truth table shows this. pq p --> q q -->(not)p f f t t f t t t t f f f t t t t
For the cross between two pea plants with purple flowers that are both heterozygous (Pp), the Punnett square would show the genotypes: PP, Pp, Pp, and pp, and the phenotypic ratio of 3 purple flowers to 1 white flower.
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
The results would be a 50% chance of offspring with genotype Pp and a 50% chance of offspring with genotype pp. This is because the parent with genotype Pp can pass on either a P or a p allele, while the parent with genotype pp can only pass on a p allele.
The sum of p and q means (p+q). The difference of p and q means (p-q).
Not sure I can do a table here but: P True, Q True then P -> Q True P True, Q False then P -> Q False P False, Q True then P -> Q True P False, Q False then P -> Q True It is the same as not(P) OR Q
q + p
If p = 50 of q then q is 2% of p.
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 5 words with the pattern Q--PP---. That is, eight letter words with 1st letter Q and 4th letter P and 5th letter P. In alphabetical order, they are: quippers quippier quipping quippish quopping
If p then q is represented as p -> q Negation of "if p then q" is represented as ~(p -> q)
P! / q!(p-q)!
Use p for a single page. For example: (p 7) Use pp for multiple pages. For example: (pp 300-301)
The assertion in the question is not always true. Multiplying (or dividing) 0 by a negative number does not yields 0, not a negative answer.Leaving that blunder aside, let p and q be positive numbers so that p*q is a positive number.Thenp*q + p*(-q) = p*[q + (-q)] = p*[q - q] = p*0 = 0that is p*q + p*(-q) = 0Thus p*(-q) is the additive opposite of p*q, and so, since p*q is positive, p*(-q) must be negative.A similar argument works for division.