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Until an "equals" sign shows up somewhere in the expression,

there's nothing to prove.

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13y ago

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Sin squared theta plus cos squared theta barabar Kya Hota Hai?

1


What is cos theta times cos theta?

Cos theta squared


How do you solve cos theta subtract cos squared theta divide 1 plus cos theta?

The question contains an expression but not an equation. An expression cannot be solved.


What does negative sine squared plus cosine squared equal?

-Sin^(2)(Theta) + Cos^(2)Theta => Cos^(2)Theta - Sin^(2)Theta Factor (Cos(Theta) - Sin(Theta))( Cos(Theta) + Sin(Theta)) #Is the Pythagorean factors . Or -Sin^(2)Theta = -(1 - Cos^(2)Theta) = Cos(2)Theta - 1 Substitute Cos^(2)Thetqa - 1 + Cos^(2) Theta = 2Cos^(2)Theta - 1


If cos and theta 0.65 what is the value of sin and theta?

You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.


What is sec squared theta times cos squared theta minus tan squared theta?

Tan^2


How do you solve theta if cos squared theta equals 1 and 0 is less than or equal to theta which is less than 2pi?

cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0


Which basic trigonometric identity is actually a statement of the pythagorean theorem?

COS squared Theta + SIN squared Theta = 1; where Theta is the angles measurement in degrees.


Prove that sin theta power 8 - cos theta power 8 equal to sin sq Theta -cos sq x 1-sin sq Theta cos sq theta?

The equation cannot be proved because of the scattered parts.


What is sin squared theta cos squared theta?

If there is a plus in between, that would be equal to 1, as a result of the Pythagorean Theorem. Otherwise, you can convert this into other forms with some of the trigonometric identities for multiplication, but you won't really get it into a simpler form.


What is cos theta minus cos theta times sin squared theta?

cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)


How would you solve and show work for cos2 theta if cos squared theta equals 1 and theta is in the 4th quadrant?

cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1