(x2+3x-4) (x-4)
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
(x-2)(x+2)= x2+2x-2x-4= x2-4
4
x2 + 2x + 2 = 0 Use the quadratic formula: x = (-2 +- sqrt(4 - 8))/2 x = (-2 +- 2i)/2 = -1 +- i
(x2+3x-4) (x-4)
2(x + 2)(x - 2)(x2 + 2x + 4)(x2 - 2x + 4)
Multiply by 4. 4x2 - 12x + 9 factors to (2x - 3)(2x - 3) or (2x - 3)2
Write it as x2 - 2x - 4 = 0, and solve with the quadratic formula (a = 1, b = -2, c = -4).
x2-2x-24 when factorised = (x+4)(x-6)
x2 - 2x - 24 = (x - 6)(x + 4)
If that's + 8x, the answer is 4(x2 + 2x - 6) If that's - 8x, the answer is 4(x2 - 2x - 6)
negative four: x2 - 2x + 5 = x2 - 2x + 5 - 4 = x2 - 2x + 1 = (x - 1)2
(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
If that's + 4x2, the answer is 2x(x2 + 2x - 4)