What I did was divide 150 by 6 (because of the six integers)
150/6 = 25
I then just subtracted one and added one to get the first two even integers
25 - 1 = 24
25 + 1 =26
Then added two to the high one and subtracted two from the low one
24 - 2 = 22
26 + 2 = 28
Repeat above step
22 - 2 = 20
28 + 2 = 30
20 + 22 + 24 + 26 + 28 + 30 = 150
It is 53. 53 + 55 + 57 + 59 + 61 + 63 = 348
For this particular problem, you just need to experiment a little. 1 + 2 + 3 + 4 + 5 +6 = 21 (6 integers).
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
7 is a whole number, six is an interger.
150.
There is no set of six consecutive integers for -4.
The integers are -14, -12 and -10.
x+(x+2)= 66.
The six consecutive integers greater than -7 are: -7, -6, -5, -4, -3, -2
Seventy-six and Seventy-eight, or 76+78 = 154
If you mean six consecutive INTEGERS, then the answer is Yes.
25, 26, 27, 28, 29, 30
It is 53. 53 + 55 + 57 + 59 + 61 + 63 = 348
-6, -4, -2, 0, 2 or -6, -8, -10, -12, -14
-6, -4, -2, 0, 2 -6, -8, -10, -12, -14
Six and seven
-3, -2, -1, 0, 1 and 2