The integers -7 and +7.
6 7
Think of 5 positive integers that have a mode of 4 and 6, a median of 6 and a mean of 7.
The four consecutive even integers are 4, 6, 8, 10. The product of 8 and 10 is 80. Algebraically, the equation to find the four integers is : [x + (x+2) + (x+4) + (x+ 6)]/4 = 7 (4x + 12) / 4 = 7 x + 3 = 7 x = 4 x+2 = 6 // x+4 = 8 // x+6 = 10
The two integers are 6 and 7.
The integers -7 and +7.
7+(-6)=1
55
The two possible answer are (-7, -6) and (6, 7).
6 7
5 and 7.
The integers are 6, 7, 8 and 9.
The integers are 5, 6, 7 and 8.
Think of 5 positive integers that have a mode of 4 and 6, a median of 6 and a mean of 7.
Oh, dude, the integers greater than -7 but less than -6 are just -6. Like, it's not rocket science. Just one lonely little number hanging out between -7 and -6, trying to fit in with the negative crew.
A sequence of five positive integers.
Are six integers. And the question is ...