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3x - 2y = 20 Substitute x = 4y into this equation: 3(4y) - 2y = 20 ie 12y - 2y = 20 10y = 20 so that y = 2 and then x = 4y gives x = 2*4 = 8
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
you can not solve this equation
You cannot solve one linear equation in two unknown variables.
This is a system of two linear equations: x+2y=11 3x-4y=-17 One way to solve this system is to solve for x (or y) in the first equation and then plug it into the second equation to solve for the other variable, which then allows us to solve for our original variable. (1) Take the first equation and solve for x: x=11-2y (2) Plug this value into the second equation: 3x-4y=3(11-2y)-4y=33-10y=-17. We see that y=5. (3) We now plug this into either equation to solve for x: From (1): x=11-2y=11-2(5)=1 We get x=1 and y=5. It's also always a good idea to plug the numbers we found into our original two equations to verify they work. Indeed, x+2y=1+2(5)=1+10=11, and 3x-4y=3(1)-4(5)=3-20=-17.
22
3x - 2y = 20 Substitute x = 4y into this equation: 3(4y) - 2y = 20 ie 12y - 2y = 20 10y = 20 so that y = 2 and then x = 4y gives x = 2*4 = 8
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
2y-3x=4
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
2y6 is an expression not an equation. This is an equation: 2y = 6 To solve that equation you divide each side of the equation by 2: 2y/2= 6/2 y = 3
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
No. There is not enough information in the equation x + 2y = 2, by itself, to solve it. There are an infinite number of solutions. A second equation, or information to allow a second equation to be derived, must be given to find a solution.
5X - 2Y = 20 -2Y = -5X + 20 Y = 5/2X - 10 set to 0 and solve for X 5/2X - 10 = 0 5/2X = 10 X = 4 My TI-84 graphs and confirms this
First determine whether the equation is a direct variation or a regular equation. 1. Direct Variations in inverse can be solved in the following. y=6x switch y with x ---> x=6y solve for y 2.Regular equations in inverse can be solved in the following. y=-2x-10 switch y with x----> x=-2y-10 add 10---> x+10=2y solve for y