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multiply the base of the triangle by the height then halve the answer.

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Q: How can you take out the area of a right angled triangle?
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Area of an isosceles right angled triangle?

The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.


Who found out how to find the area of a triangle?

Find the length of the base and the perpendicular height. Multiply together. Divide answer by 2. Area of Triangle = ½(Base x Perpendicular Height) For right angled triangles, take the length of the two shortest sides, multiply them together and divide the answer by two.


How do you solve to find a right triangle of you are given three sides?

Square the two smaller sides and add them together. Take the square root of the answer. If that is the same as the third side then you have a right angled triangle and if not, then you have not.


Why pythagoras is applicable in right angled triangle?

I won't explain it in depth but the simple answer is because if you take and identical right triangle then you can arrange them to make a rectangle. I've attached a link to an animation showing it rearranging a triangle to show the relationship.


What is the ratio of a 45-45-90 right triangle?

Not sure what you are asking. Take a look at 'The Right-angled Isosceles Triangle' under 'Sources and related links' below, and follow the 'Next' controls you will find there.


Can an Isosceles triangles may be obtuse or acute but never right?

Not true. A triangle with angles of 90, 45 and 45 is a right angled isosceles triangle. If you take a square piece of paper and fold it in half - from corner to corner - you will get this shape.


Does obtuse triangle must have greater area than an acute triangle?

yes. take an obtuse triangle that has a base of 8cm and a height of 3cm. then, take a right triangle that has a base of 3 cm and a height of 4 cm. do the math. the obtuse triangle will have a greater area. hope this helps.


How can you determine whether a triangle is a right triangle if you only know the lengths of the sides?

If it is a right angled triangle it will conform to Pythagoras' Theorm: The square of the hypotenuse = the sum of the squares on the other two sides. The hypotenuse would be the longest side, so add the two shorter sides squared together and if this equals the longest side squared then the triangle is a right angle triangle.


If you take a right triangle and move it to the right of a parallelogram what shape do it create?

If you take a right triangle and move it to the right of a parallelogram, it creates a trapezium.


What is the area of a right triangle whose legs are 10' and 15'?

Use the formula for the area of a triangle, which is 0.5 x base x height. Since the 10' and the 15' are at right angles, you can take any of them to be the "base", in which case the other one is the "height".


When you use an inclined plane is the length greater than the height?

Of course the length is greater than the height. Take the example of a right angled triangle where the hypotenuse is always greater than the other two arms.


How do you find the side of a right triangle with base and height?

square both the base and the height and add that together, and then take the square root of that answers and that's the last sideThis is called the Pythagorean Theorem: a2+b2=c2 where a and b are the legs (base and height) and c is the hypotenuse (or longest side)* * * * *That is true, but only if the triangle is a right angled triangle. In other cases, the answer is indeterminate.