multiply the base of the triangle by the height then halve the answer.
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The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
Find the length of the base and the perpendicular height. Multiply together. Divide answer by 2. Area of Triangle = ½(Base x Perpendicular Height) For right angled triangles, take the length of the two shortest sides, multiply them together and divide the answer by two.
Not sure what you are asking. Take a look at 'The Right-angled Isosceles Triangle' under 'Sources and related links' below, and follow the 'Next' controls you will find there.
Not true. A triangle with angles of 90, 45 and 45 is a right angled isosceles triangle. If you take a square piece of paper and fold it in half - from corner to corner - you will get this shape.
If you take a right triangle and move it to the right of a parallelogram, it creates a trapezium.