zero
Half the distance between them would be 4 units; so 3 units from P would not be close enough to Q to be equidistant.
The distance between the points of (4, 3) and (0, 3) is 4 units
The distance between these two points is 23.
Then one point is 20 units away from the other.
six units
Using the distance formula it is 25 units
None. If a point is 2 units from 'A' and equidistant from 'A' and 'B', then it also has to be2 units from 'B'.But the shortest distance between 'A' and 'B' is 6 units, and the point on that line that's equidistantfrom both of them is the point in the middle, which is 3 units from each.So a point equidistant from 'A' and 'B' must be 3 or more units from each one. 2 units won't do it.
The distance between the points of (4, 3) and (0, 3) is 4 units
The distance between these two points is 23.
The distance between the points of (4, 3) and (0, 3) is 4 units
Points: (-6, 1) and (-2, -2) Distance: 5 units
Points: (3, -4) and (3, 3) Distance: 7 units
4
Then one point is 20 units away from the other.
six units
Using the distance formula it is 25 units
Distance between the points of (3, 7) and (15, 16) is 15 units
The distance between points: (9, 4) and (3, 4) is 6