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The length of a rectangle is 3 inches less than twice the width If the perimeter of the rectangle is 18 inches how wide is the rectangle?
This involves solving a small system of equations. Let L represent length and W represent width. Our two equations are:
I) L = 2W - 3
II) P = 2L + 2W = 18
since the perimeter of a rectangle is the sum of twice the length and twice the width. If we substitute 2W - 3 for L in equation II, then we get:
2(2W - 3) + 2W = 18, and simplifying the right hand side we get
6W - 6 = 18
if we add 6 to both sides we get 6W = 24, and dividing both sides by 6 we get W = 4. Now, if we plug this back into equation I, we have L = 2(4) -3 = 8 - 3 = 5.
So the answer is: the length is 5 and the width is 4.
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The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
What is the perimeter in feet of a rectangle whose length is twice its width and whose width is 9 feet?
If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.
How would you find the width if you only know the perimeter and length?
If it's a rectangle, just minus the length from the perimeter twice and than divide what you have by 2. Width = (Perimeter - (length*2))/2
What happens when the perimeter of a rectangle is 36 inches if the length is twice the width what is the area in square inches of the rectanglr?
Since the perimeter of a rectangle is 2 * length + 2 * width, 2l + 2w = 36 And since the length is twice the width, l = 2w Thus, you substitute 2w into the l in the first equation to get, 2(2w) + 2w = 36 4w + 2w = 36 6w = 36 w = 6 Plug the value of w into the second equation, l = 2(6) This will give you a length of 12. Since the area of rectangle is l * w, we just substitute the values in for length and width, l * w = 6 * 12 = 72 And that would be in square inches of course.
The area of a rectangle is 36 square inches the length is 1 inch more than twice the width what are the dimensions of the rectangle?
9" x 4"
What is the perimeter of a rectangle with length 42 inches?
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
What is The length of a rectangle is 3 inches less than twice the width. If the perimeter of the rectangle is 18 inches find the width of the rectangle?
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
The length of a rectangle is 3 inches less than twice the width If the perimeter of the rectangle is 18 inches what is the width of the rectangle?
4
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
The length of a rectangle is twice its width If the perimeter of the rectangle is 54y find its area?
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
If the length of a rectangle is twice the width the perimeter is 42 inches what is the width?
2 (x + 2x) = 42 x + 2x = 21 3x = 21 Therefore, x = 7 The width of the rectangle is 7 inches. The length of the rectangle is 14 inches.
The length of a rectangle is 6 inches more than twice its width If the perimeter of the rectangle is 54 inches find the width of the rectangle?
Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)
What is the perimeter of a rectangle with a length of 12.1 in and a width of 4.6 in?
The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in
Area and perimeter of a rectangle?
Area is length times width, perimeter is twice the sum of length and breadth.
What is the perimeter of 42 Meters and length?
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
How does increasing the dimensions of a rectangle impact the perimeter?
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
What is the area of a rectangle that its perimeter is 39?
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
