Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
Suppose the angle is x degrees. Then its complement is 90 - x deg So 90 - x = 4*x ie 90 = 5x or x = 18 degrees.
25
60 degrees.
67.5 degrees
Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
15°
Complementary angles add up to 90 degrees. If one angle is five times the measure of the other, you can express their measurements as 5x and x. The original angle is x degrees and its complement is 5x degrees. Set the sum of the two angles equal to 90 and solve for x. 5x + x = 90 6x = 90 x = 15 The angle is 15 degrees. Its complement is 5(15) = 75 degrees. 75 + 15 = 90.
Suppose the angle is x degrees. Then its complement is 90 - x deg So 90 - x = 4*x ie 90 = 5x or x = 18 degrees.
go off
Suppose the angle is x then its complement is 90-x So 4*(90-x) = x or 360 - 4x = x so that 360 = 5x => x = 72 degrees
Suppose the angle is x degrees. Then its complement is x/5 deg So x + x/5 = 90 or 6x = 450 ie x = 75 degrees.
The angle= 36, the supplement= 144, the compliment=54
an angle that is 54 degrees less than 4 times its complement
25
60 degrees.
67.5 degrees