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The n x indicating the number of factors of x?
The exponent
The n in X indicating thenumber of factors of X?
nX in this case this says that n multiplys X by a factor of n Xn in this case this says that X is to the power of factor n not really another other case I can think of. Not sure what you are asking
What is the sum of the numbers from 1 to 100?
Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050
If told that 'q' 'p' and 'r' are distinct primes and that there exists 'n' such that 'n equals p x q x r' How many positive factors of 'n' are there and How do you determine what they are?
If p, q and r are distinct primes and n=pxqxr then n will have 8 factors, all of which will be positive since prime numbers are all positive, which are: n(pqr), pq, pr, qr, p, q, r and 1. Here there were 3 distinct primes so the number of positive factors is 2^3. In general if you had p distinct primes then you would have 2^p positive factors.
What is 3 consecutive even numbers that add up to 666?
669
The n x indicating the number of factors of x?
The exponent
Then n in x indicating the number of factors of x?
the exponent
What is the difference between an indicating and non-indicating piece of equipment?
The n in X" indicating the number of factors of X
The n in Xn indicating the number of factors of X?
the answer would be exponentthe n in x indicating the number of factor of x is exponent
The n in X indicating the number of factors of X is called?
The exponent
What is the n in x indicating the number of factors of x called?
The exponent
The n in x indicating the number of factors of x?
exponent exponent
The Xn indicating the number of factors of x?
yes, if you write x^n, then there are n x's multiplied together
What is the n in x indicating the number of factors of x?
There is no simple relationshipp between a number and the count of its factors.
The n in X indicating thenumber of factors of X?
nX in this case this says that n multiplys X by a factor of n Xn in this case this says that X is to the power of factor n not really another other case I can think of. Not sure what you are asking
What 3 consecutive odd numbers have a product of 29667?
The numbers can be represented as n - 2, n and n + 2 so that (n - 2)n(n + 2) = 29667 This can be expressed as n(n2 - 4) = n3 - 4n = 39667 and the roots solved for a cubic equation. However, the problem can also be solved by factoring. If the numbers are a, b and c then a x b x c = 29667 and a, b and c are clearly factors of 29667. The factors of 29667 are 3 x 11 x 29 x 31 which can be stated as 33 x 29 x 31. The three consecutive numbers are therefore 29, 31 and 33.
What is the n in xn indicating the number of factor of x?
exponent exponent
