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The product of 3 consecutive odd numbers is 12075 find the numbers?
Wiki User
∙ 15y ago
Let n be an integer. 2n - 1 will be odd.
(2n - 1) * (2(n+1) - 1) * (2(n+2) - 1) = 12075
4n^3 + 6n^2 - n - 6039 = 0
Which has 1 real root and 2 complex conjugate roots.
The real root is at n=11.
Substituting back in: 2(11) - 1 = 21
Final answer:
21 * 23 * 25 = 12075
Wiki User
∙ 15y ago
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