Let n be an integer. 2n - 1 will be odd.
(2n - 1) * (2(n+1) - 1) * (2(n+2) - 1) = 12075
4n^3 + 6n^2 - n - 6039 = 0
Which has 1 real root and 2 complex conjugate roots.
The real root is at n=11.
Substituting back in: 2(11) - 1 = 21
Final answer:
21 * 23 * 25 = 12075
27 and 28
The numbers are 14, 15, 16 and 17.
The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.
27*28 = 756
24 and 25 or -25 and -24
Find two consecutive numbers with the value of 4160
28 and 29
24,25,26
27 and 28
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
15 and 13
The numbers are 14, 15, 16 and 17.
11 and 12
The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.
27*28 = 756
64 x 65 = 4160
They are 16 and 18