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Q: The sum of 8 and y?

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8 + y

8 + 6y

5

y = 3x+8 x + y = 72 x = 16 y = 56

Let this numbers be x and y, then x + y = 52 x - y = 8 x = 8 + y x + y = 52 substitute 8 + y for x into the first equation; 8 + y + y = 52 8 + 2y = 52 subtract 8 to both sides; 2y = 44 divide by 2 to both sides; y = 22 x = 8 + y substitute 22 for y into the equation; x = 8 + 22 x = 30 Thus this numbers are 22 and 30. 22 & 30

Related questions

8 + y

ya mum

8 + 6y

5

Y = 4 (x+8)

The word sum is the clue. It means the problem will be an addition problem.y + 3(8) = ?y + 24 = ?

8y+6y is 14y

y = x +8 where x is the number

Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)

x+y=18x^2+y^2=164 x=10 and y=8 or vice versa

It is an algebraic equation.

2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y

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