16
16 + 2(sqrt16) = 24
16 + 2(4) = 24
16 + 8 = 24
It's not. Take 49 and 16 for example. The square root of the sum is the square root of 65. The sum of the square roots is 11.
Square root of 2 = 1.414213562... Square root of 7 = 2.645751311... The sum is 4.059964873...
The square root of 100 = 10 The square root of 225 = 15 The sum = 10 + 15 = 25
because ur supposed to do it thAt way buddy
Yes.
find the sum of 2 and 2
The square root of any positive integer can only be a WHOLE NUMBER or IRRATIONAL, so the square root of 7 is irrational.On the other hand, the sum of a rational and an irrational number is always irrational.
It's not. Take 49 and 16 for example. The square root of the sum is the square root of 65. The sum of the square roots is 11.
sqrt 9 = +3 or 3 3 - 7 = -4 -3-7 = -10 the sum is an integer
false
You can. Just add the numbers together, and find their square root. One plus three is four; the square root of the sum is two.
If you have a data set, simply take the square root of the sum of the squares of the data points. Let's say you have three numbers a, b, and c. RSS = SQRT(a2 + b2 + c2).
Square root of 2 = 1.414213562... Square root of 7 = 2.645751311... The sum is 4.059964873...
The square root of 100 = 10 The square root of 225 = 15 The sum = 10 + 15 = 25
9 and 10 9 + 2(10) = 29
6 6+(3*62) = 114
No. The right hand side is always greater - unless both components are zero.