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Q: The sum of an integer and twice the next consecutive integer is 29. What are the integers?

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If n is an odd integer then the next two consecutive odd integers are n+2 and n+4.

An even integer is a number that is a multiple of 2. If n is an even integer, the next consecutive even integers are n+2, n+4 and so on.

There are no two such consecutive 'integers'!!Proof: Let the first integer be x.So, the next consecutive integer is x+1.Now, as per the question : x + (x+1) = 24=> 2x=23 (After taking all constants on one side and variable terms on the other).=> x=(23/2) = 11.5So, 11.5 & 12.5 are the required numbers but they are not integers !

let x = integer and x + 2 next consecutive even integer x +(x +2) = 90 2x + 2 = 90 2x + 88 x = 44 and x+2 = 46 44 and 46

If x is the smallest odd integer, then x = 2n + 1 for some integer n. Then the next two odd integers are 2n + 3 and 2n + 5 So the question then becomes: 2n+1 + (2n+3) + (2n+5) = 45 or 6n + 9 = 45 to be solved for n and thence the smallest of the three consecutive odd integers.

Related questions

If n is an odd integer then the next two consecutive odd integers are n+2 and n+4.

An even integer is a number that is a multiple of 2. If n is an even integer, the next consecutive even integers are n+2, n+4 and so on.

Numbers one after another. Ex.: 1, 2, 3, 4, 5..........

Suppose the smallest integer is A. The next two even numbers are A+2 and A+4. Using the information supplied we can form an equation: 2A - 14 = A + A+2 + A+4 Rearranging: 2A - 14 = 3A + 6 -20 = A So the three integers are -20, -18 and -16.

There are no two such consecutive 'integers'!!Proof: Let the first integer be x.So, the next consecutive integer is x+1.Now, as per the question : x + (x+1) = 24=> 2x=23 (After taking all constants on one side and variable terms on the other).=> x=(23/2) = 11.5So, 11.5 & 12.5 are the required numbers but they are not integers !

Two consecutive integers means one is 1 more than the other integer. You can solve the problem by letting x represesnt one of the integers and x + 1 the next integer. Set up the equation and solve: x + (x + 1) = 45 (next simplify) 2x + 1 = 45 (next subtract 1 from each side of the equation) 2x = 44 (next divide both sides of the equation by 2 to solve for the first integer) x = 22 (this the first integer, the next is x + 1 which is 23) The two integers are 22 and 23 (22 + 23 + 45).

Try squaring different integers (hint: in this case, the integers will be fairly small). If you find that the square of one integer is less than 27, and the square of the next integer is more than 27, you have your answer.

let x = 1st integer x + 1 = next consecutive integer x + x + 1 = 15 2x + 1 = 15 2x = 14 x = 7 x = 1 = 8

If n is one integer, then the consecutive integer to it is n+1, and the next is n+2 and so on.

There are no such consecutive integer as is so simple to prove! Suppose the first integer is x. Then the next (consecutive) integer is x+1. Then 2*x + 4*(x+1) = 30 So that 2x + 4x + 4 = 30 6x + 4 = 30 6x = 30 - 4 = 26 x = 26/6 which is NOT an integer.

x+2

You can always guess and check! When they are consecutive, it means they must be the next odd integer up from the last. For this, it is 11, 13, 15. 11+13+15= 39

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