5 times 10 = 50 50 add 24 = 74 the answer = 5 One way you can work this out is by expressing it in algebriac form: 10X + 24 = 74 10x = 50 Thus X = 5
Suppose the number is x. The sum of the number and two is x+2 Four times the sum is 4(x+2) The number times 8 is 8x 24 less than the number times 8 is 8x-24 4(x+2) = 8x-24 4x+8=8x-24 so 4x = 32 and x = 8
24(x + 2.25)
the sum of 18 and a number equals 24
To calculate 4 times the sum of a number and 6, you would first find the sum of the number and 6, then multiply that sum by 4. Let's represent the number as 'x'. So, the sum of the number and 6 would be x + 6. Multiplying this sum by 4 gives you the expression 4(x + 6), which simplifies to 4x + 24.
Call the unknown number n. From the problem statement, 5(6 + n) = 24, or 30 + 5n = 24, or 5n = 24 - 30 = - 6, or n = -(6/5).
Suppose the number is x. The sum of the number and two is x+2 Four times the sum is 4(x+2) The number times 8 is 8x 24 less than the number times 8 is 8x-24 4(x+2) = 8x-24 4x+8=8x-24 so 4x = 32 and x = 8
24(x + 2.25)
The answer is 24.
-24
Let the number be x: 5x+x = 24 6x = 24 x = 4
the sum of 18 and a number equals 24
To calculate 4 times the sum of a number and 6, you would first find the sum of the number and 6, then multiply that sum by 4. Let's represent the number as 'x'. So, the sum of the number and 6 would be x + 6. Multiplying this sum by 4 gives you the expression 4(x + 6), which simplifies to 4x + 24.
The sum of one number must be itself, so the answer is 2.4
29
The sum of the interior angles of a polygon can be calculated using the formula ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides. For a regular 24-gon, ( n = 24 ). Therefore, the sum of the interior angles is ( (24 - 2) \times 180^\circ = 22 \times 180^\circ = 3960^\circ ).
24
Call the unknown number n. From the problem statement, 5(6 + n) = 24, or 30 + 5n = 24, or 5n = 24 - 30 = - 6, or n = -(6/5).