To begin with, let's represent the ten's digit with x. Then, we know that the one's digit is (10-x), because the sum of the digits is 10. Since the value of the ten's is 10 times more than the digit, we multiply it by 10. Now we have the original number: 10x+10-x. We can simplify it into 9x+10. For the reversed number, the digits switch spots, so now we multiply the one's by 10. The reversed # is 10(10-x)+x, which could be simplified into 100-9x.To get an equation you have to balance the two sides. For that, you need to add 18 to the original # to make it equal to the reversed #.
9x+10+18=100-9x
9x+9x=100-28
18x=82
x=82/18
x=4
The original number is 46.
The reversed number is 64.
CHECK: 64-46=18
IT WORKS!!!
192
To total 17 the two digits must be 8 and 9! The original number was 98.
11yrs.
Find a four digit number whose digits will be reversed when multiplied by nine?
Possibility of two digit no whose sum is 10 19,28,37,46,55,64,73,82,91 Now add 54 to each no mentioned above 73,82,91,100,109,118,127,136,145 See after 1st comma 28 and 82 Reverse of 28 is 82. That no 82 is 54 more than the no 28. So 28 is the original
The number is 36
17
192
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
five digits number when you multiply by four is the same the number when you reversed it is 21978*4 = 87912
To total 17 the two digits must be 8 and 9! The original number was 98.
An eight digit number with one zero cannot remain the same when its digits are reversed. It must have an even number of 0s.
after 11yrs.
11yrs.
47 Impossible problem!
Find a four digit number whose digits will be reversed when multiplied by nine?
45