The paired factors of 330 are :-
1 x 330
2 x 165
3 x 110
5 x 66
6 x 55
10 x 33
11 x 30
15 x 22
The two factors that sum to 37 are 15 & 22. The larger number is thus 22.
Alternatively, let the two numbers be a and b. Then a + b = 37, therefore a = (37 - b). Substituting for a in ab = 330 generates the quadratic equation b2 - 37b + 330 = 0.
Solving this gives b = (37 ± 7)/2 = 22 and 15. The larger number is 22.
NOTE : The equation can also be factored giving these same answers
A product cannot exist of a single number - a product is formed by multiplying two separate numbers.
The larger number is 12.
37 and 40
Multiply the number by another number and the product is the multiple
The product of the original numbers is equal to the product of the GCF and LCM. Divide the product of the LCM and GCF by the one number. The answer will be the other.
To get the product, multiply the first number by the second. To get the sum, add the second number to the first. To get the difference, subtract the smaller number from the larger.
The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).
The numbers are: 378 and 42 because (9*42)*42 = 15876
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
4,6,8,10
2 is '2 more than five times 0'; their product is zero. This would make the answer (0, 2).
To find the third number, divide the product of the three numbers by the product of the two known numbers. First, calculate the product of the known numbers: 13 × 15 = 195. Then, divide 2730 by 195: 2730 ÷ 195 = 14. Therefore, the third number is 14.
A product cannot exist of a single number - a product is formed by multiplying two separate numbers.
The larger number is 12.
Take two numbers. Throw (the first number) into a box (the second number) times. The total amount in the box is then the product of the two numbers.
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
The product of the GCF and LCM of two numbers is equal to the product of the two numbers. The other number is 126.