599 if we're talking whole nos. only
3 equal groups of 7 or vice versa, if you mean groups of even nos-no
THE ODD NOs. BETWEEN 50 AND 58 ARE 51, 53, 55 and 57
we can consider all infinite sets as equivlent sets if we go by the the cantor set theory.for eg. on a number line if we consider the nos. between 0 and 1 as a set then they are infinite. similarly the nos. between 0 and 5 can also be considered infinite and if considered as a set then they can be considered as equivalent
This question has an infinite no. of answers The most obvious is one half and one quarter. If you want to produce more, pick a number between 1 and 384; subtract it from 768. Put each of these nos. upon 1024 - you will have two fractions that add to 768/1024 =3/4. You can extend this process to get as many pairs of fractions as you like.
33and 34
there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
3,5&7 3*5*7=105
4 x 6 x 8 = 192
148
2 and 3.
777/3 = 259. So the numbers are 258, 259 and 260.
The nos. Are 8 and -8 Sum of the nos. 8+(-8)=0 Product of the nos. 8 × (-8) = -64
x + y = 5xy=41 and 4 works. ■
//sum and product of 3 nos #include #include void main() { int a,b,c; printf("enter the 3 nos"); scanf("%d%d%d",&a,&b,&c); printf("sum of 3 nos",a+b+c); printf("product of 3 nos",a*b*c); getch(); }
A composite number is an integer which is the product of two or more integers which greater than 1.
Because any number divisible by 2 is not a prime number, so any even no. is divisible by 2. Thus any number higher than 3 will be divisible by 2. Therefore the only consecutive prime nos. are 1, 2 and 3