Let the consecutive numbers be n and n+1, then
n (n + 1) = 992 : n2 + n = 992 : n2 + n - 992 = 0
This equation factors : (n + 32)(n - 31) = 0
The only positive integer solution is when n - 31 = 0, then n = 31 so n + 1 = 32
The two consecutive numbers are 31 and 32.
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599 if we're talking whole nos. only
we can consider all infinite sets as equivlent sets if we go by the the cantor set theory.for eg. on a number line if we consider the nos. between 0 and 1 as a set then they are infinite. similarly the nos. between 0 and 5 can also be considered infinite and if considered as a set then they can be considered as equivalent
This question has an infinite no. of answers The most obvious is one half and one quarter. If you want to produce more, pick a number between 1 and 384; subtract it from 768. Put each of these nos. upon 1024 - you will have two fractions that add to 768/1024 =3/4. You can extend this process to get as many pairs of fractions as you like.
There are 60 different ways of answering this question correctly! You work it out!
25 is a perfect square occurring between 20 and 30.