The two numbers are 50 and 63. Their sum is 113 and they have a difference of 13.
The two numbers would be 7 and 9. 7 times 9 = 63 7 + 9 = 16
Oh, isn't that just a happy little math problem we have here? Let's give it some color and see what we find. If the difference of the two numbers is 32 and their sum is 158, we can create a simple system of equations to solve for the numbers. One number would be 95 and the other would be 63. Just like that, we've painted a beautiful solution!
20 and 43
63/7 = 9 63 - 7 = 56 The two numbers are therefore 7 and 63.
The two numbers are 50 and 63. Their sum is 113 and they have a difference of 13.
50 and 63
The product of any two numbers is the answer to the multiplication sum. For example, in the sum 7 x 9 = 63, the number 63 is the product.
The smaller of the two numbers is 31.
63 and 64
If you mean a ratio of 5 to 3 then the two numbers are 105 and 63
63 and 7
First, we need to clarify the condition in the problem: the sum of two numbers is 16, and the difference between the two numbers is 6. Based on these conditions, we can say that these two numbers are respectively x and y. According to the problem description, we can list the following equations: The sum of the two numbers is 16, which is x plus y is equal to 16. The difference between the two numbers is 6, which is 6 xβy=6. By solving this system of equations, we get x=9 and y=7. So the product of these two numbers is 9 x 7 = 63
The two numbers would be 7 and 9. 7 times 9 = 63 7 + 9 = 16
The numbers are 21 and 63.
63.
-52 & -11