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all the numbers,are divisible by 4, 3times 4times 1,2 times 4 times 1,and2times3 times 4,one must alway's try thinking outside the box,as in this question,make 15 out of six ones?,well there are two ones in the number 11,1 in 12,1,in 13,1 in 14,1 in 15,add up the ones it makes 15
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What expression using 1234 only once to equal 8?
What is 4 divided by 1,234
How do you get 19 by only using 1234 once?
4(2+3)-1=19
How do you get the number 16 only using 1234 once?
How about: 2*(1+3+4) = 16
Maximum number that can be formed using all the digits 6 4 8 1 without repetition and which is divisible by 9?
The biggest number that can be formed with just those four digits once each, is 8641 - however - no number made from those digits can be divided by 9 because in order for a number to be exactly divisible by nine - the sum of the digits must also divide exactly by nine. The sum of the digits 6, 4 8 & 1 is 19 !Another Answer:-The above answer is absolutely correct.A possible solution is 61+8/4 = 63 and 7*9 = 63
How many 2-digit or 3-digit numbers can be formed using the digits 134568 and 9 which are diisible by 4?
48. Assuming no digit can be used more than once, the two digit numbers divisible by 4 are: 16, 36, 48, 56, 64, 68, 84, 96 8 of them. For any number to be divisible by 4, only the last two digits need be divisible by 4; so for three digit numbers, each of the two digit numbers above can be preceded by any of the remaining 5 digits and still be divisible by 4. → 5 x 8 = 40 three digit numbers are divisible by 4 → 40 + 8 = 48 two or three digit numbers made up of the digits {1, 3, 4, 5, 6, 8, 9} are divisible by 4. If repeats are allowed, there are an extra 2 two digit numbers (44 and 88) and each of the two digit numbers can be preceded by any of the 7 digits, making a total of 7 x 10 + 10 = 80 two and three digits numbers divisible by 4 make up of digits from the given set.
