(x-y) + (xy - 1) = (x - 1)(y + 1)
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Xy/y = x
xy + x + y + 1 = (x + 1)(y + 1).
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
The GCF is xy
xy = x ÷x y = 1
It is XY^2 or X*Y*Y
x+xy=8 xy=-x+8 y=-1+8/x
(x-y) + (xy - 1) = (x - 1)(y + 1)
*Hint*=xy=x mutiplied by y.
xy + x = x(y + 1)
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Xy/y = x
xy + x + y + 1 = (x + 1)(y + 1).
That is irrelevant, there is not possible way y=xy, and there is no possible way xy=x.