(x-y) + (xy - 1) = (x - 1)(y + 1)
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Xy/y = x
xy + x + y + 1 = (x + 1)(y + 1).
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
The GCF is xy
xy = x ÷x y = 1
It is XY^2 or X*Y*Y
(x-y) + (xy - 1) = (x - 1)(y + 1)
*Hint*=xy=x mutiplied by y.
x+xy=8 xy=-x+8 y=-1+8/x
Oh, what a happy little question! To factor out xy from xy, you simply take out the common factor, which is xy itself. So, the factored form of xy is just xy. Isn't that just lovely? Just remember, there are no mistakes in math, only happy little accidents.
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Xy/y = x
xy + x + y + 1 = (x + 1)(y + 1).
That is irrelevant, there is not possible way y=xy, and there is no possible way xy=x.