x - the smallest
x+2 - the middle
x+4 - the largest
3x=5+2(x+4)
3x=5+2x+8
3x-2x=5+8
x=13 -the smaller
13+2=15-the middle
13+4=17- the largest
5872345098234783904672083946728390752430689723409687298290843 theres your answer
x + (x + 2) + (x + 4) = 5 (x + 4) so 3x + 6 = 5x + 20 ie -2x = 14 so x = -7 and integers are -7, -5 and -3 Sneaky!
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
The sum of three consecutive integers is -72
If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer. Let the smallest integer be x, then the others are x + 2 and x+ 4. Therefore 4x - (x + 4) = 2 (x + 2 ) + 4 Expanding, we get 4x -x -4 = 2x + 4 + 4 Gathering terms: x = 12 Thus the three integers are 12, 14 and 16.
5872345098234783904672083946728390752430689723409687298290843 theres your answer
You've come to the right place. The integers are: 2, 4, and 6
x+(n+1)+3(n+2)= something then solve,
249
The 3 consecutive odd positive integers are 7, 9 and 11.
Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.
x + (x + 2) + (x + 4) = 5 (x + 4) so 3x + 6 = 5x + 20 ie -2x = 14 so x = -7 and integers are -7, -5 and -3 Sneaky!
98
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
The sum of three consecutive integers is -72
Let x be the middle integer: 3(x+1) = 7(x-1) 3x + 3 = 7x - 7 3x + 10 = 7x 10 = 4x So the middle one is 10/4 which is not an integer. So there is really no solution.
9,11,13