answersLogoWhite

0

200*30 = 6000

200*6 = 1200

50*30 = 1500

50*6 = 300

1*30 = 30

1*6 = 6

User Avatar

Wiki User

10y ago

What else can I help you with?

Related Questions

What are the partial products of 36 x 57?

They are: 30*50, 30*7, 6*50 and 6*7.


Which are partial products for 734x29?

The partial products for 734X29 are 6,606 and 14,680.


What are the partial products for 51 and 36?

50 x 30 = 1500 50 x 6 = 300 1 x 30 = 30 1 x 6 = 6


What are the partial products for 51 x 36?

50 x 30 = 1500 50 x 6 = 300 30 x 1 = 30 6 x 1 = 6


What are the partial products of 35 X 7?

how to find the partial products of a number


What is partial products of 87 times 65?

Partial products of 87 times 65 would be 80 x 60 and 80 x 5 and 7 x 60 and 7 x 5. Partial products allow for the multiplication of whole numbers.


Show me the numbers that are the partial products of 77x30?

To find the partial products of 77 x 30, we can break down the numbers into their place values. We can express 77 as 70 + 7 and 30 as 30. The partial products are: 70 x 30 = 2100 and 7 x 30 = 210. Thus, the partial products of 77 x 30 are 2100 and 210.


What are partial products for 128 x 43?

To find the partial products for 128 x 43, you can break down the multiplication into simpler components. First, split 43 into 40 and 3. Then, calculate the partial products: 128 x 40 = 5120 and 128 x 3 = 384. Finally, add the partial products together: 5120 + 384 = 5504, so 128 x 43 = 5504.


What are partial products for 77 x 30?

700 and 210 are the answers to partial products of 77 times 30


What is the partial products of 30x82?

To find the partial products of 30 x 82, you can break down the numbers into simpler components. First, you can express 82 as 80 + 2. Then, calculate the partial products: 30 x 80 = 2400 and 30 x 2 = 60. Finally, add the partial products together: 2400 + 60 = 2460.


What are the partial products of 43 x 28?

To find the partial products of 43 x 28, we can break down the numbers into tens and units. The calculation can be expressed as (40 + 3) x (20 + 8). This results in four partial products: 40 x 20 = 800, 40 x 8 = 320, 3 x 20 = 60, and 3 x 8 = 24. Adding these partial products together gives 800 + 320 + 60 + 24 = 1204.


How do you use partial products to solve 3x12?

3 x 10 = 30 + 3 x 2 = 6 3 x 12 = 36