There are 24 permutations with four digits, assuming no repetition:
These are as follows:
{1,2,3,9} {1,2,9,3} {1,3,2,9} {1,3,9,2}
{1,9,2,3} {1,9,3,2} {2,1,3,9} {2,1,9,3}
{2,3,1,9} {2,3,9,1} {2,9,1,3} {2,9,3,1}
{3,1,2,9} {3,1,9,2} {3,2,1,9} {3,2,9,1}
{3,9,1,2} {3,9,2,1} {9,1,2,3} {9,1,3,2}
{9,2,1,3} {9,2,3,1} {9,3,1,2} {9,3,2,1}
The formula to work out permutation without repetition is n! / (n - r)!.
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
There are 840 4-digit combinations without repeating any digit in the combinations.
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
There are 210 4 digit combinations and 5040 different 4 digit codes.
To calculate the number of 4-digit combinations that can be made with 4 digits, we can use the formula for permutations. Since there are 10 possible digits (0-9) for each of the 4 positions, the total number of combinations is 10^4, which equals 10,000. This is because each digit can be selected independently for each position, resulting in a total of 10 choices for each of the 4 positions.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
10,000
-11
"There are 10,000 different combinations"-Hey nick! love dave and jalp
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
There are 840 4-digit combinations without repeating any digit in the combinations.
The answer is 10C4 = 10!/[4!*6!] = 210
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
There are 210 4 digit combinations and 5040 different 4 digit codes.
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
To calculate the number of 4-digit combinations that can be made with 4 digits, we can use the formula for permutations. Since there are 10 possible digits (0-9) for each of the 4 positions, the total number of combinations is 10^4, which equals 10,000. This is because each digit can be selected independently for each position, resulting in a total of 10 choices for each of the 4 positions.
You would get 4!/2! = 12 combinations.