There are 24 permutations with four digits, assuming no repetition:
These are as follows:
{1,2,3,9} {1,2,9,3} {1,3,2,9} {1,3,9,2}
{1,9,2,3} {1,9,3,2} {2,1,3,9} {2,1,9,3}
{2,3,1,9} {2,3,9,1} {2,9,1,3} {2,9,3,1}
{3,1,2,9} {3,1,9,2} {3,2,1,9} {3,2,9,1}
{3,9,1,2} {3,9,2,1} {9,1,2,3} {9,1,3,2}
{9,2,1,3} {9,2,3,1} {9,3,1,2} {9,3,2,1}
The formula to work out permutation without repetition is n! / (n - r)!.
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
There are 840 4-digit combinations without repeating any digit in the combinations.
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
There are 210 4 digit combinations and 5040 different 4 digit codes.
9,000 - all the numbers between 1,000 and 9,999 inclusive. * * * * * NO. Those are PERMUTATIONS, not COMBINATIONS. Also, the question specified 4 digit combinations using 4 digits. The above answer uses 10 digits. If you start with 4 digits, you can make only 1 combination.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
10,000
-11
Oh, isn't that just lovely? You can create so many beautiful combinations using the numbers 1 through 9. Just think of all the possibilities waiting to be discovered! Keep exploring and let your imagination run wild with all the different combinations you can come up with.
"There are 10,000 different combinations"-Hey nick! love dave and jalp
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
There are 840 4-digit combinations without repeating any digit in the combinations.
The answer is 10C4 = 10!/[4!*6!] = 210
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
There are 210 4 digit combinations and 5040 different 4 digit codes.
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
9,000 - all the numbers between 1,000 and 9,999 inclusive. * * * * * NO. Those are PERMUTATIONS, not COMBINATIONS. Also, the question specified 4 digit combinations using 4 digits. The above answer uses 10 digits. If you start with 4 digits, you can make only 1 combination.