The 2-dimensional coordinates of p are (xp, yp) and those of Q are (xQ, yQ). I am not sure how that might help, but with the information provided that is the best that can be done.
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The point with coordinates (p, q) will be rotated to the point with coordinates [(p - q)/sqrt(2), (p + q)/sqrt(2)].
True
zero Half the distance between them would be 4 units; so 3 units from P would not be close enough to Q to be equidistant.
q + p
If p then q is represented as p -> q Negation of "if p then q" is represented as ~(p -> q)