Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
the multiples of 4 are 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60 those are the multiples of 4
12, 24, and 36
4, 8 and 12 are the first 3 common multiples of 2 and 4
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
The highest power of 25 that divides the product of the first 100 multiples of 5 is 50. This is because for each multiple of 25, we have an extra factor of 25. Since there are 4 multiples of 25 in the first 100 multiples of 5, we have a total of 50 factors of 25.
25 and 50
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
the multiples of 4 are 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60 those are the multiples of 4
12, 24, and 36
It is 75.
the first six multiples of 4 are 4,8,12,16,20,24
25%
25, 50, 75, 100
The first three multiples of 4 are 4, 8 and 12. For them to be common, they need to be compared to another set of multiples.
The first three multiples of 4 are 4, 8 and 12. For them to be common, they need to be compared to another set of multiples.