Assuming that you start with 1, then n = 1, 2, 3, 4, 5, and 4-8n = -4, -12, -20, -28, -36
5
10,11,12,13,14 or 8,10,12,14,16
The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
5
If that is + 192 then divide all terms by 3 and it is (x+8)(x+8) when factored
All but John Adams served two terms. The total of the first five was nine terms or 36 years (almost - Washington's first term was about an month short.)
There is no city at 48N 4E. Instead, there is a forest, which is located a few miles to the north of Bernon, France.
Yes, here's the proof. Let's start out with the basic inequality 36 < 48 < 49. Now, we'll take the square root of this inequality: 6 < √48 < 7. If you subtract all numbers by 6, you get: 0 < √48 - 6 < 1. If √48 is rational, then it can be expressed as a fraction of two integers, m/n. This next part is the only remotely tricky part of this proof, so pay attention. We're going to assume that m/n is in its most reduced form; i.e., that the value for n is the smallest it can be and still be able to represent √48. Therefore, √48n must be an integer, and n must be the smallest multiple of √48 to make this true. If you don't understand this part, read it again, because this is the heart of the proof. Now, we're going to multiply √48n by (√48 - 6). This gives 48n - 6√48n. Well, 48n is an integer, and, as we explained above, √48n is also an integer, so 6√48n is an integer too; therefore, 48n - 6√48n is an integer as well. We're going to rearrange this expression to (√48n - 6n)√48 and then set the term (√48n - 6n) equal to p, for simplicity. This gives us the expression √48p, which is equal to 48n - 6√48n, and is an integer. Remember, from above, that 0 < √48 - 6 < 1. If we multiply this inequality by n, we get 0 < √48n - 6n < n, or, from what we defined above, 0 < p < n. This means that p < n and thus √48p < √48n. We've already determined that both √48p and √48n are integers, but recall that we said n was the smallest multiple of √48 to yield an integer value. Thus, √48p < √48n is a contradiction; therefore √48 can't be rational and so must be irrational. Q.E.D.
7
Paris
2,1,0 is th sequence of its terms
5
no clue
What does N equal? Well to solve the problem you would do N+7x1, N+7x2, N+7x 3, N+7x4, N+7x5 to figure out the first five terms.
Paris, France
354, 708, 1062, 1416, 1770.