There are too many to list (1,286) but here are some of them: 1001, 1008, 1015, 1022, 1029, 1036, 1043, 1050, 1057, 1064, 1071, 1078, 1085, 1092, 1099, 1106 . . .
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There are 2828 integers between 1000 and 9999.
Smallest multiple of 7 greater than 100 is 15 Largest multiple of 7 less than 1000 is 142 So number of multiples of 7 = 142 - 15 + 1 = 128
68 of them.
The last "x7" under 100 is 14 x 7, the last under 1000 is 142 x 7, so there are 128 in the range.
428 of them.
There are 2828 integers between 1000 and 9999.
1001, 1014, 10027 and just keep adding 13 till you get to 9997.
Prime No: between 1000 to 9999= 54_( 42x3)
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
Well, honey, to find the number of 4-digit multiples of 9, you just need to divide the largest 4-digit multiple of 9 (9999) by 9 and subtract the smallest 4-digit multiple of 9 (1008) divided by 9. So, 9999 ÷ 9 - 1008 ÷ 9 = 1111 - 112 = 999. That's right, there are 999 4-digit numbers that are multiples of 9.
9*9*8*7 = 4536
128!
They are members of the set of numbers of the form 7*k where k is an integer which takes 1000 different values..
There are 10 palindromes divisible by 9 between 1000 and 9999.
Smallest multiple of 7 greater than 100 is 15 Largest multiple of 7 less than 1000 is 142 So number of multiples of 7 = 142 - 15 + 1 = 128
from 1000 to 9999, ie 9999 - 999 = 9000
There are 143 such numbers, too many to list.