The partial products of 28 x 14 are 112 and 280.
28 = 8 + 20
⇒ 28 x 14 = 8 x 14 + 20 x 14
= 112 + 280
14 = 4 + 10
⇒ 28 x 14 = 28 x 4 + 28 x 10
= 112 + 280
The partial products are the same in the different splits as 28 = 2 x 14.
If the numbers had been, say, 17 x 28 then:
28 = 8 + 20
⇒ 28 x 17 = 8 x 17 + 20 x 17
= 136 + 340
17 = 7 + 10
⇒ 28 x 17 = 28 x 7 + 28 x 10
= 196 + 280
They are 600, 240, 80 and 32.
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
28 (:
14 times.
The largest whole number that can go into these three number, 28, 42, and 70 is:142 times 14 equals 283 times 14 equals 425 times 14 equals 70Or it could be 28 if you allowed non-whole numbers in the equation:1 times 28 equals 281.5 times 28 equals 422.5 times 28 equals 70
To find the partial products for the multiplication of 34 and 28, you can break down the numbers into their place values. For example, 34 can be expressed as 30 and 4, while 28 can be expressed as 20 and 8. The partial products would then be calculated as follows: (30 \times 20 = 600), (30 \times 8 = 240), (4 \times 20 = 80), and (4 \times 8 = 32). These partial products are 600, 240, 80, and 32.
To find the partial products of 42 and 28, you can break down each number into its place values. For 42, you have 40 and 2, and for 28, you have 20 and 8. The partial products are calculated as follows: (40 \times 20 = 800), (40 \times 8 = 320), (2 \times 20 = 40), and (2 \times 8 = 16). Adding these together, (800 + 320 + 40 + 16 = 1176).
To find the partial products of 48 times 28, we can break down the numbers. We can express 48 as 40 + 8 and 28 as 20 + 8. Then, we calculate the partial products: 40 × 20 = 800 40 × 8 = 320 8 × 20 = 160 8 × 8 = 64 Adding these together gives 800 + 320 + 160 + 64 = 1344. Thus, the product of 48 and 28 is 1344.
To find the partial products of 28 and 43, you can break down the multiplication into simpler parts. First, multiply 28 by 3 (the tens place of 43), which gives you 84 (28 × 3). Then, multiply 28 by 40 (the tens place of 43 multiplied by 10), resulting in 1120 (28 × 40). The partial products are 84 and 1120.
6
They are 600, 240, 80 and 32.
It is: 28 times 14 = 392
14 multiplied by 28 is 392
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
The number of times 14 can go into 28 can be calculated by dividing 28 by 14. This division results in 2, indicating that 14 can go into 28 exactly 2 times without any remainder. Therefore, 14 can go into 28 twice.
28 (:
14 times.