To find the partial products of 28 times 14, you would multiply each digit in the ones place of the second number (4) by each digit in the ones place of the first number (8), resulting in 32. Next, you would multiply each digit in the tens place of the second number (1) by each digit in the ones place of the first number (8), resulting in 8. Finally, you would add these two products together to get the final answer of 392.
They are 600, 240, 80 and 32.
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
28 (:
14 times.
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
6
They are 600, 240, 80 and 32.
It is: 28 times 14 = 392
14 multiplied by 28 is 392
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
28 (:
14 times.
The number of times 14 can go into 28 can be calculated by dividing 28 by 14. This division results in 2, indicating that 14 can go into 28 exactly 2 times without any remainder. Therefore, 14 can go into 28 twice.
They are: 30*20, 30*8, 2*20 and 2*8.
28
126 times 28=3,528 126 * 28 1008 +2520 3,528
2 times 14 equals 28. This is because multiplication is a mathematical operation that involves repeated addition. In this case, multiplying 2 by 14 means adding 2 to itself 14 times, resulting in a total of 28.