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To find the partial products of 28 times 14, you would multiply each digit in the ones place of the second number (4) by each digit in the ones place of the first number (8), resulting in 32. Next, you would multiply each digit in the tens place of the second number (1) by each digit in the ones place of the first number (8), resulting in 8. Finally, you would add these two products together to get the final answer of 392.
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JordanThe partial products of 28 x 14 are 112 and 280.
28 = 8 + 20
⇒ 28 x 14 = 8 x 14 + 20 x 14
= 112 + 280
14 = 4 + 10
⇒ 28 x 14 = 28 x 4 + 28 x 10
= 112 + 280
The partial products are the same in the different splits as 28 = 2 x 14.
If the numbers had been, say, 17 x 28 then:
28 = 8 + 20
⇒ 28 x 17 = 8 x 17 + 20 x 17
= 136 + 340
17 = 7 + 10
⇒ 28 x 17 = 28 x 7 + 28 x 10
= 196 + 280
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What are partial products for 34 28?
They are 600, 240, 80 and 32.
Partial products for 34 28?
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
What is 14 times 2?
28 (:
How many times can 2 go into 28?
14 times.
What arethe Partial products of 4x27?
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
