Oh, what a happy little question! On a 3-number lock, there are 1,000 possible combinations. Isn't that just wonderful to think about? Just remember to take your time and enjoy the process of finding the right combination, like painting a beautiful landscape!
There are 6C3 = 20 such combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 7C4 = 7!/(4!*3!) = 7*6*5/(3*2*1) = 35 combinations.
13579
To determine the number of combinations of 3 words, we need to know the total number of words available. Let's say we have a pool of n words. The formula to calculate the number of combinations of 3 words without repetition is n! / (3!(n-3)!), where "!" denotes factorial. This formula accounts for the number of ways we can select 3 words from a pool of n without repetition.
Just one. * * * * * Depends on how many numbers are on each ring. If there are x numbers, then the total number of combinations (actually they are permutations) is x*x*x or x3.
All the numbers from 000 to 999 (inclusive).
There are 6C3 = 20 such combinations.
10.
All the possible digits (10 of them; 0-9) are multiplied by themselves by the number of digits that can be shown in the lock. (3) This is 103, or 1,000. This certainly shows why guessing is not a good way to break into a numerical lock, especially since three is a rather low number of digits for one!
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
You Can Create 999 Number combinations
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
There are: 12345C3 = 3.134847985*1011
6 of them.
4*3*2*1 = 24 different combinations.