When two dies are thrown, there are 36 possible outcomes. The first number represents the outcome of the first die and the second number represents the outcome of the second die.
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
11 outcomes if the dice are indistinguishable, 36 otherwise.
The set of possible outcomes is the set of different ways in which an event might or might not happen. Take a very simple example: If you roll a dice you will roll a 6 or a 5 or a 4 or a 3 or a 2 or a 1. So there are 6 different possible outcomes, all of which are equally probable. If you roll 2 dice at the same time the possible total scores are are from 2 ( a 1 and a 1) to 12 (a 6 and a 6), so there are 11 possible outcomes, but not all equally probable.
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
There are 36 outcomes for rolling 2 dice, and there is 1 way that a 12 can occur which is 6,6. So, the probability of rolling the sum of 12 on 2 dice is 1/36.
11 outcomes if the dice are indistinguishable, 36 otherwise.
The set of possible outcomes is the set of different ways in which an event might or might not happen. Take a very simple example: If you roll a dice you will roll a 6 or a 5 or a 4 or a 3 or a 2 or a 1. So there are 6 different possible outcomes, all of which are equally probable. If you roll 2 dice at the same time the possible total scores are are from 2 ( a 1 and a 1) to 12 (a 6 and a 6), so there are 11 possible outcomes, but not all equally probable.
There are 6 outcomes with one roll and 6^2 with two and 6^3 with three. So the answer is 216.
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
There is 4 ways to roll a 9 with 2 dice, and 36 possible outcomes. So, the probability of rolling a sum of 9 with two dice is 4/36 or 1/9.
All possible outcomes: 2,3,4,5,6,7,8,9,10,11,12 All possible outcomes that are prime: 2,3,5,7,11 All possible rolls that are one of these prime numbers: --1-2-3-4-5-6 1.*.*....*....* 2.*....*....*... 3....*....*...... 4.*....*......... 5....*..........* 6.*..........*... So we count 15 possible ways to make a prime number. P = (# of correct outcomes) / (# of total possible outcomes) P = 15 / (6*6) = 0.416667 or 5/12
There are 36 outcomes for rolling 2 dice, and there is 1 way that a 12 can occur which is 6,6. So, the probability of rolling the sum of 12 on 2 dice is 1/36.
The odds of not rolling a 1 or 2 with two dice is 35 in 36. The odds of doing that 25 times in a row is (35/36)25 or about 0.4945Note: The odds of not rolling a 1 is zero, so the answer degraded to the odds of not rolling a 2.===================================Opinion #2:-- There are 36 possible outcomes when 2 dice are rolled.-- Only one of the outcomes is a 2.-- So the probability of NOT rolling a 2 with 2 dice is 35/36 .-- In 25 consecutive rolls, the probability of never rolling a 2 is (35/36)25 = 49.45% .-- The 'odds' are 1,011 to 989 against it.
The largest possible sum with 2 six sided dice is 12.
Three possible outcomes:WinLooseDraw
3
There are technically 8 possible outcomes if you are talking about the side of the coin it lands on. Each coin has 2 possible outcomes (landing on heads and landing on tails). To figure out the number of outcomes for all the coins you multiply the outcomes for all of the coins together: 2 X 2 X 2= 8.