When two dies are thrown, there are 36 possible outcomes. The first number represents the outcome of the first die and the second number represents the outcome of the second die.
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
11 outcomes if the dice are indistinguishable, 36 otherwise.
The set of possible outcomes is the set of different ways in which an event might or might not happen. Take a very simple example: If you roll a dice you will roll a 6 or a 5 or a 4 or a 3 or a 2 or a 1. So there are 6 different possible outcomes, all of which are equally probable. If you roll 2 dice at the same time the possible total scores are are from 2 ( a 1 and a 1) to 12 (a 6 and a 6), so there are 11 possible outcomes, but not all equally probable.
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
There are 36 outcomes for rolling 2 dice, and there is 1 way that a 12 can occur which is 6,6. So, the probability of rolling the sum of 12 on 2 dice is 1/36.
The sum can be any number from 2 to 12.That's 11 possible outcomes.
There are eleven possible "sums of dots" if you throw two 6-sided dice. The range of possible values is from 2 (1+1) to 12 (6+6).
There are 36 possible outcomes.
There is 62 or 36 possible outcomes rolling two dice.
6 sides x 6 sides = 36 outcomes
there are 36 outcomes when rolling 2 dice
11 outcomes if the dice are indistinguishable, 36 otherwise.
The set of possible outcomes is the set of different ways in which an event might or might not happen. Take a very simple example: If you roll a dice you will roll a 6 or a 5 or a 4 or a 3 or a 2 or a 1. So there are 6 different possible outcomes, all of which are equally probable. If you roll 2 dice at the same time the possible total scores are are from 2 ( a 1 and a 1) to 12 (a 6 and a 6), so there are 11 possible outcomes, but not all equally probable.
1/36.Explanation: There will be 36 possible outcomes when you roll two dice.Let us suppose the first number is the outcome of 1 dice and the second number is the outcome of the second dice. Then we have 36 possible outcomes like : (1,1) , (1,2), (1,3), (1,4), (1,5), (1,6) and so on until (6,6). Note that 6 is the highest possible outcome on any dice.When you add the outcomes of both dice you are supposed to get two. In such a case only one outcome is possible of all the 36 outcomes and that is (1,1).Now, by definition, Probability is (No. of favorable outcomes/Total number of outcomes) = 1/36 in this case.
There are 6 outcomes with one roll and 6^2 with two and 6^3 with three. So the answer is 216.
Since there are 11 different outcomes it is possible that the first eleven throws are all different. But the 12th time you throw must repeat one of the previous results.
1, 2, 3, 4, 5, 6