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120 has three prime factors: 2, 3 and 5.
To find the prime factors of 120, start with any 2 factors of 120:
2 X 60 is a good start. Then, keep factoring until all factors are prime numbers:
2 X 60
2 X 2 X 30
2 X 2 X 2 X 15
2 X 2 X 2 X 3 X 5
The prime factorization of 120 is 2 X 2 X 2 X 3 X 5
The prime numbers (factors) of 120 are: 2,3,5
120=(12)*(10)
(12)*(10)=(3*4)*(5*2)
(3*4)*(5*2)=(3*[2*2])*(5*2)
So the prime factorization is 2*2*2*3*5.
But the answer you are looking for is simply: 2, 3, and 5.
The number 120 as a product of its prime factors is: 2 x 2 x 2 x 3 x 5
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How do write a number for example 120 as a product of its prime factors and give answers in index notation?
As a product of its prime factors: 23*3*5 = 120
How do you find the prime factorization of 120 using exponents?
As a product of its prime factors using exponents: 2^3 times 3 times 5 = 120
What is the HCF of 120 and 180?
The Highest Common Factor (HCF) of 120 and 180 is the largest number that divides both 120 and 180 without leaving a remainder. To find the HCF, we need to factorize both numbers into their prime factors. The prime factorization of 120 is 2^3 * 3 * 5, and the prime factorization of 180 is 2^2 * 3^2 * 5. To find the HCF, we take the product of the common prime factors with the lowest exponent, which is 2^2 * 3 = 12. Therefore, the HCF of 120 and 180 is 12.
How do you know that 30 is a factor of 120 explain your answer in words?
30 is 2*3*5. 120 is 2^3*3*5. As all the prime factors of 120 appear with a smaller or equal multiplicity in 30, 30 is a factor of 120.
What is the HCF of 120 and 65?
The Highest Common Factor (HCF) of 120 and 65 is the largest positive integer that divides both 120 and 65 without leaving a remainder. To find the HCF, you can use the Euclidean algorithm or prime factorization method. In this case, the prime factorization of 120 is 2^3 * 3 * 5 and the prime factorization of 65 is 5 * 13. The common factors are 5, so the HCF of 120 and 65 is 5.
