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120 has three prime factors: 2, 3 and 5.

To find the prime factors of 120, start with any 2 factors of 120:

2 X 60 is a good start. Then, keep factoring until all factors are prime numbers:

2 X 60

2 X 2 X 30

2 X 2 X 2 X 15

2 X 2 X 2 X 3 X 5

The prime factorization of 120 is 2 X 2 X 2 X 3 X 5
The prime numbers (factors) of 120 are: 2,3,5
120=(12)*(10)

(12)*(10)=(3*4)*(5*2)

(3*4)*(5*2)=(3*[2*2])*(5*2)

So the prime factorization is 2*2*2*3*5.

But the answer you are looking for is simply: 2, 3, and 5.
The number 120 as a product of its prime factors is: 2 x 2 x 2 x 3 x 5

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Its prime factors are 2, 3 and 5

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10y ago
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Q: What are the prime factors of 120?
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