From everything I can see in the question, it appears that 80,000 is a whole, real, rational,
natural integer, and a constant. The magnitude of its range and its domain are both zero,
and its upper and lower bounds are both the same number, namely 80,000 .
The lower bound for 1 significant figure for the number 90000 would be 80000. This is because when rounding to 1 significant figure, we look at the first non-zero digit from the left, which in this case is 9. To determine the lower bound, we keep the 9 in the same place and replace all other digits to the right with zeros.
The upper bound of 9 to the nearest integer is 9, as 9 itself is already an integer. The lower bound of 9 to the nearest integer is also 9, as there is no smaller integer that 9 can be rounded down to. Therefore, both the upper and lower bounds of 9 to the nearest integer are 9.
identifying any upper or lower bounds on the decision variables
124.68 significant figures means figures after the decimal, in the case after the 8, if the number after the significant figure is 4 or lower the last SF (significant figure) stays the same, if 5 or higher then you add one. for example the number 124.683 to one SF is 124.7, because 8 means you round the last number up (add one) * * * * * The above answer could no be more incorrect! It has confused decimal digits with significant digits. 124.683, to 2 sig digits is 120. The two non-zero numbers 1 and 2 and everything else 0.
under 5 billion = 0 more than 5 billion = 10 billion this is higher and lower bounds. Sorry if I misinterpreted
Lower and Upper bound of 1000 of two significant figures is 100Plus or minus 50 is 950 , 1050
The lower bound for 1 significant figure for the number 90000 would be 80000. This is because when rounding to 1 significant figure, we look at the first non-zero digit from the left, which in this case is 9. To determine the lower bound, we keep the 9 in the same place and replace all other digits to the right with zeros.
In science, the number of significant figures in a measurement indicates the level of precision. 0.5m has one significant figure, implying a lower precision compared to 0.50m, which has two significant figures. The additional zero in 0.50m conveys that the measurement is known to the nearest hundredth of a meter.
1950 to 2049
How do you calculate the upper and lower bounds? Image result for How to find the upper and lower bound of 1000? In order to find the upper and lower bounds of a rounded number: Identify the place value of the degree of accuracy stated. Divide this place value by
20000000 400 80000 Lower are 20,40,60. ~Becca
no won noes * * * * * It means that there is an upper and lower bound or limit. There is the lower bound such that you exclude any smaller numbers, and an upper bound such that you exclude bigger numbers. What you do wit hnumbers that are equal to the bounds depends on the nature of the bounds.
The Lower fence is the "lower limit" and the Upper fence is the "upper limit" of data, and any data lying outside these defined bounds can be considered an outlier.
The lower bound is 0.5 less and the upper bound is 0.5 more.
The upper bound of 9 to the nearest integer is 9, as 9 itself is already an integer. The lower bound of 9 to the nearest integer is also 9, as there is no smaller integer that 9 can be rounded down to. Therefore, both the upper and lower bounds of 9 to the nearest integer are 9.
identifying any upper or lower bounds on the decision variables
124.68 significant figures means figures after the decimal, in the case after the 8, if the number after the significant figure is 4 or lower the last SF (significant figure) stays the same, if 5 or higher then you add one. for example the number 124.683 to one SF is 124.7, because 8 means you round the last number up (add one) * * * * * The above answer could no be more incorrect! It has confused decimal digits with significant digits. 124.683, to 2 sig digits is 120. The two non-zero numbers 1 and 2 and everything else 0.